I want to print out some address on a value. The following is what I got and got to print out what I want.
// I need the first address to start with zero.
void printoutAddr(char* x, int n, int sign) {
printf(" Address +x00 +x04\n");
intptr_t y = (intptr_t)x;
// to round it down every 16 byte
char *z = (char *)((y + 15)&~15);
// or char *z = (char *)(y&~15);
if (sign>0) {
for (int i=0; i<n; i++) {
printf("%p %.08x %.08x\n"
, (char *)(z+16*i)
, *(char *)(z+16*i)
, *(char *)(z+4+16*i);
}
} else {
for (int i=n; i>0; i--) {
printf("%p %.08x %.08x\n"
, (char *)(z+16*i)
, *(char *)(z+16*i)
, *(char *)(z+4+16*i);
}
}
}
And output is like the following:
dumper outputs...
Address +x00 +x04
0x7fff5ad8c980 000000b8 000000ff
0x7fff5ad8c990 000000a8 000000ff
0x7fff5ad8c9a0 000000e1 000000ff
0x7fff5ad8c9b0 00000001 00000000
0x7fff5ad8c9c0 00000000 00000000
But this looks ugly and I need to do this using union. And I get stuck trying the following.
void printoutAddr(char* x, int n, int sign) {
printf(" Address +x00 +x04\n");
intptr_t y = (intptr_t)x;
char *z = (char *)((y + 15)&~15);
union ptrs {
char * ptr ;
int num ;
} xptr ;
xptr.ptr = z;
xptr.num = n;
if (sign>0) {
for (int i=0; i<n; i++) {
printf("%p %.08x %.08x\n"
, (char *)(xptr.ptr+16*i)
, *(char *)(xptr.ptr+16*i)
, *(char *)(xptr.ptr+4+16*i));
}
} else {
for (int i=n; i>0; i--) {
printf("%p %.08x %.08x\n"
, (char *)(xptr.ptr+16*i)
, *(char *)(xptr.ptr+16*i)
, *(char *)(xptr.ptr+4+16*i));
}
}
}
I am getting the error of
on the line printf("%p %.08x %.08x\n"
of Thread 1: EXC_BAD_ACCESS
And don't know how to fix it...
Is there any other way to print out the same thing using unions like above?
A union can hold either member, but not both. Which one is up to you (usually tracked in a separate variable).
Note that
xptr.ptr = z;
xptr.num = n;
corrupts the value of ptr
, so when you later refer to it, it holds the wrong data, which leads to your BAD ACCESS error.