Say I have a:
std::vector<std::vector<int> > indices;
I fill these up, where each index of both outer and inner vectors have 3 entries. Now I want to do something similar to applying std:move_backward() on single vector-containers.
Let me give an example. Here is my initial container filled at the following indices:
[0][0][0][1][0][2] , [1][0][1][1][1][2] , [2][0][2][1][2][2] , [3][0][3][0][3][0]
After moving from an i-th element backwards, in this example: the outer-index [1], I would get:
[0][0][0][1][0][2] , [1][0][1][1][1][2] , [1][0][1][1][1][2] , [2][0][2][1][2][2]
Basically, the outer-index [1] is placed in [2], and [3] is replaced by the original [2], moving the inner-vectors along with it.
Any ideas on how this can be done? Perhaps with a function template?
This should do what you describe:
std::copy_backward(indices.begin()+1, indices.begin()+3, indices.end());
No special manipulation of the inner vector is necessary.