I have some old C code that still runs very fast. One of the things it does is store the part of an array for which a condition holds (a 'masked' copy)
So the C code is:
int *msk;
int msk_size;
double *ori;
double out[msk_size];
...
for ( int i=0; i<msk_size; i++ )
out[i] = ori[msk[i]];
When I was 'modernising' this code, I figured that there would be a way to do this in C++11 with iterators that don't need to use index counters. But there does not seem to be a shorter way to do this with std::for_each
or even std::copy
.
Is there a way to write this up more concisely in C++11? Or should I stop looking and leave the old code in?
I think you are looking for std::transfrom
.
std::array<int, msk_size> msk;
std::array<double, msk_size> out;
double *ori;
....
std::transform(std::begin(msk), std::end(msk),
std::begin(out),
[&](int i) { return ori[i]; });