Finding letters in an array

Question

I am trying to make a program, that lets me type in 10 characters and stores them in an array. just single characters are enough, for example (d, s, a, e, h, j, e,). and then lets me look for one of the chars using linear search algorithm and gives out the position within the array.

I tried to program it but I can only do it with integers. here is my code so far.

I don't know how to change it to letters / characters?

public static void main(String args[])

int c, n, search, array[];

Scanner in = new Scanner(System.in);
System.out.println("Enter number of elements");
n = in.nextInt(); 
array = new int[n];

System.out.println("Enter " + n + " Letters");

for (c = 0; c < n; c++)
  array[c] = in.nextInt();

System.out.println("What letter do you want to find?");
search = in.nextInt();

for (c = 0; c < n; c++)
{
  if (array[c] == search)     /* Searching element is present */
  {
     System.out.println(search + " is present at location " + (c + 1) + ".");
      break;
  }
if (c == n)  /* Searching element is absent */
  System.out.println(search + " Letter is not found.");

Answer 1

I tried to program it but I can only do it with integers

No, you can do it if you use in.next().charAt(0) rather than in.nextInt() from Scanner Class to take the first Character form String.

I don't know how to change it to letters / characters?

Here you don't need to change it, or some regex or split it, the method in.next() get the String from the input (end-use) and then get the charAt(0) the first one.

Now, what i have changed in your code to be worked as you mentioned above:

1. Change search and array[] to char Data type.
2. Change the declaration of array[] to array = new char[n]
3. Change the input for search and array to in.next().charAt(0).

Try this:

 public static void main(String args[]) {

    int n,c;
    char search,array[];

    Scanner in = new Scanner(System.in);
    System.out.println("Enter number of elements");
     n = in.nextInt();
    array = new char[n];

    System.out.println("Enter " + n + " Letters");

    for ( c = 0; c < n; c++) {
        array[c] = in.next().charAt(0);
    }

    System.out.println("What letter do you want to find?");
    search = in.next().charAt(0);

    for ( c = 0; c < n; c++) {
        if (array[c] == search) /* Searching element is present */ {
            System.out.println(search + " is present at location " + (c + 1) + ".");
            break;
        }
        if (c == n) /* Searching element is absent */ {
            System.out.println(search + " Letter is not found.");
        }
    }
}