Understanding arguments of QMetaObject :: invokeMethod - QtQuick

Question

From: http://qt-project.org/doc/qt-4.8/qtbinding.html#calling-functions

QMetaObject :: invokeMethod (object, "myQmlFunction", Q_RETURN_ARG(QVariant, returnedValue), Q_ARG(QVariant, msg));

but, the function arguments say:

From: http://qt-project.org/doc/qt-4.8/qmetaobject.html#invokeMethod

bool QMetaObject::invokeMethod ( QObject * obj, const char * member, Qt::ConnectionType type, QGenericReturnArgument ret, QGenericArgument val0 = QGenericArgument( 0 ), QGenericArgument val1 = QGenericArgument(), QGenericArgument val2 = QGenericArgument(), QGenericArgument val3 = QGenericArgument(), QGenericArgument val4 = QGenericArgument(), QGenericArgument val5 = QGenericArgument(), QGenericArgument val6 = QGenericArgument(), QGenericArgument val7 = QGenericArgument(), QGenericArgument val8 = QGenericArgument(), QGenericArgument val9 = QGenericArgument() ) [static]

So, the third argument to this function is:
Qt::ConnectionType

How does Q_RETURN_ARG (QVariant, returnedValue) correspond to Qt::ConnectionType?

Answer 1

look again at the documentation there are multiple overloads of invokeMethod including one for:

bool QMetaObject::invokeMethod ( QObject * obj, const char * member, 
               QGenericReturnArgument ret, 
               QGenericArgument val0 = QGenericArgument( 0 ), 
               QGenericArgument val1 = QGenericArgument(), 
               QGenericArgument val2 = QGenericArgument(), 
               QGenericArgument val3 = QGenericArgument(), 
               QGenericArgument val4 = QGenericArgument(), 
               QGenericArgument val5 = QGenericArgument(), 
               QGenericArgument val6 = QGenericArgument(), 
               QGenericArgument val7 = QGenericArgument(), 
               QGenericArgument val8 = QGenericArgument(), 
               QGenericArgument val9 = QGenericArgument() ) [static]

so the caller doesn't need to specify the connection type and/or care about the return argument