How can I import an arbitrary python source file (whose filename could contain any characters, and does not always ends with .py
) in Python 3.3+?
I used imp.load_module
as follows:
>>> import imp
>>> path = '/tmp/a-b.txt'
>>> with open(path, 'U') as f:
... mod = imp.load_module('a_b', f, path, ('.py', 'U', imp.PY_SOURCE))
...
>>> mod
<module 'a_b' from '/tmp/a-b.txt'>
It still works in Python 3.3, but according to imp.load_module
documentation, it is deprecated:
Deprecated since version 3.3: Unneeded as loaders should be used to load modules and find_module() is deprecated.
and imp
module documentation recommends to use importlib
:
Note New programs should use importlib rather than this module.
What is the proper way to load an arbitrary python source file in Python 3.3+ without using the deprecated imp.load_module
function?
Found a solution from importlib
test code.
Using importlib.machinery.SourceFileLoader:
>>> import importlib.machinery
>>> loader = importlib.machinery.SourceFileLoader('a_b', '/tmp/a-b.txt')
>>> mod = loader.load_module()
>>> mod
<module 'a_b' from '/tmp/a-b.txt'>
NOTE: only works in Python 3.3+.
UPDATE Loader.load_module
is deprecated since Python 3.4. Use Loader.exec_module
instead:
>>> import types
>>> import importlib.machinery
>>> loader = importlib.machinery.SourceFileLoader('a_b', '/tmp/a-b.txt')
>>> mod = types.ModuleType(loader.name)
>>> loader.exec_module(mod)
>>> mod
<module 'a_b'>
>>> import importlib.machinery
>>> import importlib.util
>>> loader = importlib.machinery.SourceFileLoader('a_b', '/tmp/a-b.txt')
>>> spec = importlib.util.spec_from_loader(loader.name, loader)
>>> mod = importlib.util.module_from_spec(spec)
>>> loader.exec_module(mod)
>>> mod
<module 'a_b' from '/tmp/a-b.txt'>