I'm completely new to C and I'm working on a program which has to read in 3 lines from a text file(two numbers and a mathematical symbol) and write out the result. So for example:
The text file looks like:
1
4
*
and my program should be able to read the 3 lines and write out something like "1*4 = 4" or something.
I managed to get to a point where i can read the 3 lines in and show them on screen, so I thought I should put the two numbers in one array and the symbol in another one. The problem is, that I tried to see if the arrays contain the numbers I put in them and my output has some huge numbers in it and I'm not sure why.
Here's the code i wrote:
#include <stdio.h>
#include <io.h>
#include <string.h>
int main(void)
{
int res = 1; /*Creates an integer to hold the result of the check for the file*/
const char *file = "input.txt"; /*String holding the name of the file with the input data*/
res = access(file,R_OK); /*Checks if the file "input.txt" exists*/
if(res == -1)
{ /*IF the file doesn't exist:*/
FILE *input = fopen("input.txt","w"); /*This creates a file called "input.txt" in the directory of the program*/
char write[] = "1\n1\n+"; /*This variable holds the string that's to be written to the file*/
fprintf(input,"%s",write); /*This writes the variable "write" to the file*/
printf("input.txt file created!"); /*Tells you the file is created*/
fclose(input); /*Closes the file after it's done*/
}
else
{ /*IF the file exists:*/
FILE *f = fopen("input.txt","r");
//char line[ 5000 ];
//while ( fgets ( line, sizeof line, f ) != NULL )
//{
// fputs ( line, stdout );
//}
char line[5000];
char nums[2];
char symbol[1];
int i = 0;
while(fgets(line,sizeof line,f)!=NULL)
{
i++;
if(i < 3)
{
fputs(nums,f);
}
else
{
fputs(symbol,f);
}
printf("%d,%d",nums,symbol);
}
printf("\n\n\n");
scanf("\n");
}
return 0;
}
Any help would be greatly appreciated! Thank you in advance If you require any more information i will provide it.
What are you reading from the files are simply characters codes: the program has no way of figuring by itself that the character "4" corresponds to the integer number 4. The %d placeholder of printf expects int variables, or it won't work.
If you want just to print the characters you have to save them in char variables (or a char array) and use the placeholder %c in printf. If you want to actually use the numbers and symbols in your program you have more work to do.
Not only in C, but I think in most languages you have to "parse" the characters to numbers.
In C you can use the functions atoi or atol (you have to #include <stdlib.h>
) in order to do this conversion.
In order to parse the symbol I'm afraid you will have to use an if or a switch to read the character and perform the operation accordingly.
For example your loop could look like:
while(fgets(line,sizeof line,f)!=NULL)
{
int op1;
int op2;
int res;
char symbol;
i++;
switch (i) {
case 1:
//First line is first operand
op1 = atoi(line);
printf("op1 %d\n",op1);
break;
case 3:
//Second line is second operand
op2 = atoi(line);
printf("op2 %d\n",op2);
break;
//Fifth line is the operator, could be +,-,%./ or anything
case 5:
symbol = line[0];
printf("operand %c\n",symbol);
switch(symbol) {
case '+':
res = op1+op2;
break;
case '-':
res = op1-op2;
break;
default:
//operation not defined, return
return;
}
printf("%d%c%d = %d",op1,symbol,op2,res);
}
}