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bashshellheadbsd

bash shell display first part of file using BSD head

Here's the file:

line1
line2
⋮
line10
Total
Update time

I want to have the first part of file except for the last 2 lines.

The output should look like this:

line1
line2
⋮
line10

How can i achieve this using BSD head? or other oneliner?

Thanks!

Solution

  • using awk, this will print all the lines except last two lines.

      awk '{a[j++]=$0}END{for(i=0;i<j-2;i++){print a[i]}}' filename