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c++c++11namespacessfinaeoverload-resolution

SFINAE: checking the existence of a function breaks when the overload is moved to other namespaces


I want to check for the existence of a function in a specific namespace using SFINAE. I have found SFINAE to test a free function from another namespace which does the job, but there are some things I don't understand.

Currently I have this working code, straight from the linked question:

// switch to 0 to test the other case
#define ENABLE_FOO_BAR 1

namespace foo {
  #if ENABLE_FOO_BAR
    int bar();
  #endif
}

namespace detail_overload {
  template<typename... Args> void bar(Args&&...);
}
namespace detail {
  using namespace detail_overload;
  using namespace foo;
  template<typename T> decltype(bar()) test(T);
  template<typename> void test(...);
}
static constexpr bool has_foo_bar = std::is_same<decltype(detail::test<int>(0)), int>::value;

static_assert(has_foo_bar == ENABLE_FOO_BAR, "something went wrong");

(the ENABLE_FOO_BAR macro is just for testing purpose, in my real code I don't have such a macro available otherwise I wouldn't be using SFINAE)


However, as soon as I put detail_overload::bar() in any other namespace (adjusting the using directive as needed), the detection breaks silently and the static_assert kicks in when foo::bar() exists. It only works when the "dummy" bar() overload is directly in the global namespace, or part of the ::detail_overload namespace (note the global :: scope).

// breaks
namespace feature_test {
  namespace detail_overload {
    template<typename... Args> void bar(Args&&...);
  }
  namespace detail {
    using namespace detail_overload;
    using namespace foo;
    //...

// breaks
namespace feature_test {
  template<typename... Args> void bar(Args&&...);
  namespace detail {
    using namespace foo;
    //...

// breaks
namespace detail {
  namespace detail_overload {
    template<typename... Args> void bar(Args&&...);
  }
  using namespace detail_overload;
  using namespace foo;
  //...

// works
template<typename... Args> void bar(Args&&...);
namespace feature_test {
  namespace detail {
    using namespace foo;
    //...

// works
namespace detail_overload {
  template<typename... Args> void bar(Args&&...);
}
namespace feature_test {
  namespace detail {
    using namespace detail_overload;
    using namespace foo;
    //...

I realize this is the very same problem as the question I linked to, and as mentioned I already have a working solution, but what is not addressed there is why precisely does this happen?

As a side question, is there any way to achieve correct SFINAE detection without polluting the global namespace with either bar() or a detail_overload namespace? As you can guess from the non-working examples, I'd like to neatly wrap everything in a single feature_test namespace.


Solution

  • I'll change it slightly so the fall-back declaration of bar isn't a template (= shorter code), and don't use SFINAE as this is purely a name lookup issue.

    namespace foo {
        int bar(int);
    }
    
    namespace feature_test {
        namespace detail_overload {
            void bar(...);
        }
    
        namespace detail {
            using namespace detail_overload;
            using namespace foo;
    
            void test() { bar(0); } // (A)
        }
    }
    

    In line (A), the compiler needs to find the name bar. How is it looked up? It's not argument-dependent, so it must be unqualified lookup: [basic.lookup.unqual]/2

    The declarations from the namespace nominated by a using-directive become visible in a namespace enclosing the using-directive; see 7.3.4. For the purpose of the unqualified name lookup rules described in 3.4.1, the declarations from the namespace nominated by the using-directive are considered members of that enclosing namespace.

    Note they become in an enclosing namespace, not the enclosing namespace. The details from [namespace.udir]/2 reveal the issue:

    [...] During unqualified name lookup (3.4.1), the names appear as if they were declared in the nearest enclosing namespace which contains both the using-directive and the nominated namespace.

    That is, for the name lookup of bar inside test:

    namespace foo {
        int bar(int);
    }
    
    // as if
    using foo::bar;
    namespace feature_test {
        namespace detail_overload {
            void bar(...);
        }
    
        // as if
        using detail_overload::bar;
        namespace detail {
            // resolved
            // using namespace detail_overload;
            // using namespace foo;
    
            void test() { bar(0); } // (A)
        }
    }
    

    Therefore, the name bar found in feature_test hides the name (not) found in the global scope.

    Note: Maybe you can hack around this issue with argument-dependent name lookup (and a second SFINAE). If something comes to my mind, I'll add it.