Must I call atomic load/store explicitly?

Question

C++11 introduced the std::atomic<> template library. The standard specifies the store() and load() operations to atomically set / get a variable shared by more than one thread.

My question is: are assignment and access operations also atomic? Namely, given

std::atomic<bool> stop(false);

• Is !stop.load() equivalent to !stop?
• Is stop.store(true) equivalent to stop = true?

Answer 1

Are assignment and access operations for non-reference types also atomic?

Yes, they are. atomic<T>::operator T and atomic<T>::operator= are equivalent to atomic<T>::load and atomic<T>::store respectively. All the operators are implemented in the atomic class such that they will use atomic operations as you would expect.

I'm not sure what you mean about "non-reference" types? Not sure how reference types are relevant here.