feof() on Linux return true at one line later than the ending line

Question

I'm a beginner of C. When I use this while loop to print the contains of a file. The last line will print twice on Linux. It should not get into while loop when reach the end of file. It has no problem on windows.

#include <stdio.h>
#include <unistd.h>

int main()
{

    char string[400];
    FILE *file_para;

    // Open the file
    if ((file_para = fopen("Test.txt", "r")) == NULL)
    {
        printf("cannot open file\n");
        getchar();
        return 0;
    }

    while (!feof(file_para))
    {
        fgets(string, 400, file_para);
        printf("**** %s", string);
    }

    fclose(file_para);
    getchar();
    return 0;
}

Answer 1

This is the wrong way to use feof(). Use feof() to detect what went wrong after one of the main I/O functions failed. It does not predict whether you're about to reach EOF; it tells you when some I/O function has already reported EOF. C is not Pascal; in Pascal, you can (must?) check for EOF before calling the I/O functions.

while (fgets(string, sizeof(string), file_para) != 0)
{
    ...do printing, etc...
}
// If you need to, use `feof()` and `ferror()` to sort out what went wrong.

If you really, really insist on using feof(), then you also need to check your I/O operation:

while (!feof(file_para))
{
    if (fgets(string, sizeof(string), file_para) == 0)
        break;
    ...do printing, etc...
}

Note that you might be failing because ferror(file_para) evaluates to true even when feof(file_para) does not...so maybe you need while (!feof(file_para) && !ferror(file_para)), but that really is just more evidence that the while loop should be conditioned on the I/O function, not feof().