Apologies in advance if this question has already been explored here - I looked at different answers here but couldn't find what I need.
My goal is to create a dictionary like this -- {'a':[10, 9, 10, 10], 'b':[10, 9, 1, 0], 'c':[0, 5, 0, 1], and so on}
What I have is multiple dictionaries with duplicate keys (same keys in every other dictionary), something like this
{'a':10, 'b': 0, 'c': 2}
{'a':7, 'b': 4, 'c': 4}
{'a':4, 'b': 5, 'c': 3}
I have no way of knowing the number of such dictionaries, or if there are keys continuing up to 'f', or a 'g' in them but I know that the keys are duplicated. I've tried defaultdict
but what I get is--
defaultdict(<type 'list'>, {'a': [10]})
defaultdict(<type 'list'>, {'a': [10], 'b': [3]})
defaultdict(<type 'list'>, {'a': [10], 'b': [3], 'c': [0]})
and then the same thing for the next dictionary --
defaultdict(<type 'list'>, {'a': [4]})
defaultdict(<type 'list'>, {'a': [4], 'b': [5]})
defaultdict(<type 'list'>, {'a': [4], 'b': [5], 'c': [1]})
The code I have for the above output is --
d = collections.defaultdict(list)
for k, v in z.iteritems():
d[k].append(v)
c = d.items()
print d
If I do a print c
instead (to print the d.items()
) I get --
[('a', [10])]
[('a', [10]), ('b', [3])]
[('a', [10]), ('c', [0]), ('b', [3])]
which is again repeated for each dictionary. How do I get 1 dict holding all the keys, values --
{'a':[10,0,..], 'b':[4, 3, 4,..], etc.} ?
I should also add that the dicts I have are the result of a for loop and not stored individually in a unique variable.
If I understand correctly your attetion, you are trying to merge various dictionaries. One way using built-ins (I am sure that soon someone will give you a numpy
and collections
answer) could look like this:
ds = [
{'a':10, 'b': 0, 'c': 2},
{'a':7, 'b': 4, 'c': 4},
{'a':4, 'b': 5, 'c': 3} ]
merged = {}
for d in ds:
for k, v in d.items ():
if k not in merged: merged [k] = []
merged [k].append (v)
print (merged)
(Quite verbose for clarity)
EDIT: After having read your comment stating "The result I want is a list of values/key.", you can use this on the resulting merged dictionary:
print ( [ (v, k) for k, v in merged.items () ] )
This yields:
[([10, 7, 4], 'a'), ([2, 4, 3], 'c'), ([0, 4, 5], 'b')]