While updating a column 'client_name' in client table i got following error;
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE client-id=2' at line 1
Here's the code:
if ((isset($_POST["MM_update"])) && ($_POST["MM_update"] == "form1")) {
$updateSQL = sprintf("UPDATE client SET client_name=%s, WHERE client-id=%s",
GetSQLValueString($_POST['newcust'], "text"),
GetSQLValueString($_POST['select'], "int"));
mysql_select_db($database_trackntrace, $trackntrace);
$Result1 = mysql_query($updateSQL, $trackntrace) or die(mysql_error()); }
I am unable to rectify the error, need a little help.
Thanks
You have an additional ,
comma remove this
UPDATE client SET client_name=%s, WHERE client-id=%s
to
UPDATE client SET client_name=%s WHERE client-id=%s