PHP - Declare function in class based on condition

Question

Is there a way to do something like this:

class Test {
    if(!empty($somevariable)) {
        public function somefunction() {

        }
    }
}

I know this might not be best practice, but I need to do this for a very specific problem I have, so is there anyway to do it?

I just want that function to be included in the class if that variable (which is tied to a URL param) is not empty. As it is written now, I get Error: syntax error, unexpected T_VARIABLE, expecting T_FUNCTION

Thanks!

Answer 1

It depends on the your specific use case, and I don't have enough info to give a specific answer, but I can think of one possible fix.

Extend the class, using an if statement. Put everything except the one function in AbstractTest.

<?php
abstract class AbstractTest 
{
    // Rest of your code in here
}

if (!empty($somevariable)) {
    class Test extends AbstractTest {
        public function somefunction() {

        }
    }
} else {
    class Test extends AbstractTest { }
}

Now, the class Test only has the method somefunction if $somevariable isn't empty. Otherwise it directly extends AbstractTest and doesn't add the new method.