The variable y may take a value which is in a defined range:
3<y<5
The value of y should be determined introducing a constraint like
|x-y|=min
x is given and should scan a larger range like:
x:=-1000:1:1000
How do I find the exact y-value with a given x?
The results that I consider is like:
x y
-1000 3
. 3
. 3
2.9 3
3 3
3.1 3.1
4 4
5 5
6 5
7 5
. 5
. 5
1000 5
Which means I want to allow a larger "error" but between 3 and 5 it should solve with a very smaller error so that I can resolve this area fine as possible.
What would be the best way to implement something like this in Matlab? Without "IF"-condition and if possible, symbolically. But also numerical alternatives would be interesting.
Based on your comment and example I think you are simply looking for this:
x = -10:0.1:10 %Suppose this is your x
y = max(min(x,5),3) %Force it between 3 and 5 by rounding up or down respectively