IsPlainObject, thing?

Question

Does this fn:

function isplainobj ( obj ) {
    return Object.prototype.toString.call( obj ) === "[object Object]";
}

do the same thing as jQuery's: $.isPlainObject() ?

Answer 1

No, it doesn't.

Here is it's implementation:

isPlainObject: function( obj ) {
    var key;

    // Must be an Object.
    // Because of IE, we also have to check the presence of the constructor property.
    // Make sure that DOM nodes and window objects don't pass through, as well
    if ( !obj || jQuery.type(obj) !== "object" || obj.nodeType || jQuery.isWindow( obj ) ) {
        return false;
    }

    try {
        // Not own constructor property must be Object
        if ( obj.constructor &&
            !core_hasOwn.call(obj, "constructor") &&
            !core_hasOwn.call(obj.constructor.prototype, "isPrototypeOf") ) {
            return false;
        }
    } catch ( e ) {
        // IE8,9 Will throw exceptions on certain host objects #9897
        return false;
    }

    // Support: IE<9
    // Handle iteration over inherited properties before own properties.
    if ( jQuery.support.ownLast ) {
        for ( key in obj ) {
            return core_hasOwn.call( obj, key );
        }
    }

    // Own properties are enumerated firstly, so to speed up,
    // if last one is own, then all properties are own.
    for ( key in obj ) {}

    return key === undefined || core_hasOwn.call( obj, key );
},

It checks if it's type is object, if it has or not a constructor and if its properties are own properties.

For example with your function an instance of a class will return true but in this case, because it has a constructor it will return false.