Linux Shell-Script code is not executing as it should

Question

Bubble Sort : (Original Code)

clear
echo "Enter size : "
read size
echo "Enter elements : "
for (( i=0; i<size; i++ ))
do
    echo "Element " $i " : "
    read arr[$i]
done
m=$(($n-1))
for (( i=0; i<m; i++ ))
do
    cond=$((size-$i-1))
    for (( j=0; j<cond; j++ ))
    do
        l=$(($j+1));
        if [ ${a[$j]} -gt ${a[$l]} ]
        then
            tmp=${a[$j]}
            a[$j]=${a[$l]}
            a[$l]=$tmp
        fi
    done
done
echo "Sorted Data : "
echo ${a[*]}

This code is executing, while it takes the input and stores them in the array. The the next thing I see is, "Sorted Array" being printed. and no elements are printed after that.

Tried, sh -x sort.sh and the interim code isn't being executed. I am quite new to shell script and cannot understand what's wrong.

Bubble Sort : (Corrected Code)

clear
echo "Enter size : "
read size
echo "Enter elements : "
for (( i=0; i<size; i++ ))
do
    echo "Element " $i " : "
    read arr[$i]
done
m=$(($size-1))
for (( i=0; i<m; i++ ))
do
    cond=$(($size-$i-1))
    for (( j=0; j<cond; j++ ))
    do
        l=$(($j+1));
        if [ ${arr[$j]} -gt ${arr[$l]} ]
        then
            tmp=${arr[$j]}
            arr[$j]=${arr[$l]}
            arr[$l]=$tmp
        fi
    done
done
echo "Sorted Data : "
echo ${arr[*]}

Answer 1

Two things that are wrong in your program:

1. Line No. 8 - You are calling your array arr[] but later referring it as a[] . Change one of the names to match the other.
2. Line No. 10 - There is no $n in your program. You mean $size. Change this as well.

I think your program should work after this.