Python - Check if all elements in a list satisfy an inequality

Question

I have a list T = [[2,5],[4,7],[8,6],[34,74],[32,35],[24,7],[12,5],[0,34]], and i want to check if all elements in each embedded list within T satisfy an inequality.

So far i have:

upper = 10
lower = 0
for n in range(len(T)):
    if all(lower < x < upper for x in T):
        'do something'
    else:
        'do something different'

So if all elements in each T[n] are between 0 and 10, i want to do something and if else then i want to do something else. In the list above T[0],T[1] and T[2] would satisfy the inequality whereas T[3] would not.

Answer 1

You are almost there. Just replace range(len(T)) with T to iterate over the T list and check for the nested elements in the if condition, as follows :

>>> T = [[2,5],[4,7],[8,6],[34,74],[32,35],[24,7],[12,5],[0,34]]
>>> upper = 10
>>> lower = 0
>>> for elem in T:
        if all(lower < x < upper for x in elem):
            print "True", elem
        else:
            print "False", elem


True [2, 5]
True [4, 7]
True [8, 6]
False [34, 74]
False [32, 35]
False [24, 7]
False [12, 5]
False [0, 34]