XmlDoucment how to get bottom xmlnodes?

Question

In xml document, I want to get the Bottom xml node, how can I get the last xml nodes

<Books>
  <book>
    <author> sasi </author>
    <pdate>2013-01-02</pdate>
  </book>
  <book>
    <author> surya</author>
    <pdate> 2013-02-02</pdate>
  </book>
  <book>
    <author>dolly</author>
    <pdate> 2013-04-01</pdate>
  </book>
</Books>

from the above I want get the last <book> node in the xml document.

Answer 1

Try this:

var xml = @"<Books>
                <book>
                  <author> sasi </author>
                  <pdate>2013-01-02</pdate>
                </book>
                <book>
                  <author> surya</author>
                  <pdate> 2013-02-02</pdate>
                </book>
                <book>
                  <author>dolly</author>
                  <pdate> 2013-04-01</pdate>
                </book>
            </Books>";
var doc = new XmlDocument();
doc.LoadXml(xml);
var node = doc.FirstChild.LastChild;
Console.WriteLine(node.OuterXml);

Outputs:

<book><author>dolly</author><pdate> 2013-04-01</pdate></book>

Alternatively, you may select the last book child under the Books element:

doc.SelectSingleNode("Books/book[last()]")

or the last book element no matter where they are in the document:

doc.SelectSingleNode("//book[last()]");