How can I conditionally execute code in a "with" block?

I guess this is kinda abusing the feature, but I'm still curious whether it could be done - I want to do something like:

with conditional(a):
    print 1

so that the print 1 part is executed only if a==True. Is this possible?

EDIT: Like people state below, this is horrible style. It's just a riddle\question. Don't try this at home, not for the faint of heart etc.

Solution

There's no real reason to do that, since conditionals are already supplied using the if statement:

if a == True:
    print 1

But, if you're just asking for fun, the answer is you can't really. To stop the with content from executing, conditional will need to somehow stop execution, in its __enter__ method. But the only way it can do that is raising an exception, which means no other code will run, unless you wrap the with with a try statement for handling cases a != True

Edit: seeing I was prosecuted in the comments and votes for using the OP's condition (a == True) I considered changing it to if a, which is of course the idiom in Python for testing conditionals. But, we do not know what the OP had in mind, and whether he really does want a to be a boolean, and doesn't want block to execute if a = [1] (which will pass if a) I decided to leave it as is.