I have made a record type called graph
, and I have defined a suitable "is a subgraph of" relation. I would like to show that the set of graphs together with the subgraph relation forms an order, i.e. is an instance of the ord
class. But I can't get it to work. Here is my minimal working example:
theory John imports
Main
begin
typedecl node
record graph =
nodes :: "node set"
edges :: "(node × node) set"
definition subgraph :: "graph ⇒ graph ⇒ bool"
(infix "⊑" 50)
where
"G ⊑ H ≡
nodes G ⊆ nodes H ∧ edges G ⊆ edges H"
lemma "(GREATEST H. H ⊑ G) = G"
oops
end
I get the error:
Type unification failed: No type arity graph_ext :: ord"
I tried typing things like instantiation graph :: ord
and instantiation graph_ext :: ord
, but nothing seems to work. Any ideas?
When a record graph
is defined, behind the scenes a new type 'a graph_ext
is actually created. This type is the same as your record type, but with an extra field that allows extra data to be tacked in (i.e., a new field with type 'a
is added to your record definition, which can be used to add additional data into your records later on). The type graph
is simply an abbreviation for unit graph_ext
.
This means that when you want to instantiate a graph
into a type class, you actually need to instantiate the underlying type 'a graph_ext
. This could be done as follows:
instantiation graph_ext :: (type) ord
begin
instance ..
end
Although you probably also want to provide some definitions for the ord
type, perhaps as follows:
instantiation graph_ext :: (type) ord
begin
definition "less_eq_graph_ext (G :: 'a graph_ext) (H :: 'a graph_ext) ≡
nodes G ⊆ nodes H ∧ edges G ⊆ edges H"
definition "less_graph_ext (G :: 'a graph_ext) (H :: 'a graph_ext)
≡ (nodes G ⊆ nodes H ∧ edges G ⊆ edges H) ∧
¬ (nodes H ⊆ nodes G ∧ edges H ⊆ edges G)"
instance ..
end
Once 'a graph_ext
has been instantiated into the class ord
, your final lemma type-checks (although to actually carry out the proof, you likely need to do a bit more work, such as instantiating 'a graph_ext
into the preorder
or order
classes.)