Regex match everything after

Question

I have a url for which i want to match a certain pattern

/events/display/id/featured

where

• match everything after /events/
• display is matched into key
• id and featured are 1 or more matched into a key

thus i end up with

Array (
 [method] => display
[param] => Array ([0]=>id,[1]=>featured,[2]=>true /* if there was another path */)
)

so far i have

(?:/events/)/(?P<method>.*?)/(?P<parameter>.*?)([^/].*?)

But its not working out as expected.

What's wrong with the syntax?

P.S. no i don't want to use parse_url() or php defined function i need a regex

Answer 1

You can use this pattern:

<pre><?php
$subject = '/events/display/id1/param1/id2/param2/id3/param3';

$pattern = '~/events/(?<method>[^/]+)|\G(?!\A)/(?<id>[^/]+)/(?<param>[^/]+)~';

preg_match_all($pattern, $subject, $matches, PREG_SET_ORDER);

foreach($matches as $match) {
    if (empty($match['method'])) {
        $keyval[] = array('id'=>$match['id'], 'param'=>$match['param']);
    } else {
        $result['method'] = $match['method'];
    }
}
if (isset($keyval)) $result['param'] = $keyval;
print_r($result);

pattern details:

~
/events/(?<method>[^/]+)   # "events" followed by the method name 
|                          # OR
\G                         # a contiguous match from the precedent
(?!\A)                     # not at the start of the string
/(?<id>[^/]+)              # id
/(?<param>[^/]+)           # param
~