i need to draw a polygon of "n" sides given 2 points (the center and 1 of his vertex) just that i suck in math. I have been reading a lot and all this is what i have been able to figure it (i dont know if it is correct):
Ok, i take the distance between the 2 points (radius) with the theorem of Pythagoras:
sqrt(pow(abs(x - xc), 2) + pow(abs(y - yc), 2));
And the angle between this 2 points with atan2, like this:
atan2(abs(y - yc), abs(x - xc));
Where xc, yc is the center point and x, y is the only vertex know.
And with that data i do:
void polygon(int xc, int yc, int radius, double angle, int sides)
{
int i;
double ang = 360/sides; //Every vertex is about "ang" degrees from each other
radian = 180/M_PI;
int points_x[7]; //Here i store the calculated vertexs
int points_y[7]; //Here i store the calculated vertexs
/*Here i calculate the vertexs of the polygon*/
for(i=0; i<sides; i++)
{
points_x[i] = xc + ceil(radius * cos(angle/radian));
points_y[i] = yc + ceil(radius * sin(angle/radian));
angle = angle+ang;
}
/*Here i draw the polygon with the know vertexs just calculated*/
for(i=0; i<sides-1; i++)
line(points_x[i], points_y[i], points_x[i+1], points_y[i+1]);
line(points_y[i], points_x[i], points_x[0], points_y[0]);
}
The problem is that the program dont work correctly because it draw the lines not like a polygon.
Someone how know enough of math to give a hand? im working in this graphics primitives with C and turbo C.
Edit: i dont want to fill the polygon, just draw it.
Consider what 360/sides actually returns if sides is not a factor of 360 (this is integer division - see what 360/7 actually returns).
There is no need to use degrees at all - use 2*Math_PI/(double)nsides and work throughout in radians.
also you can omit the final line by using the modulus function (module nsides).
If you have more than 7 sides you will not be able to store all the points. You don't need to store all the points if you are simply drawing the polygon rather than storing it - just the last point and the current one.