Here's a simple assembly language program i have written:
section .text
global main ;must be declared for linker (ld)
main: ;tells linker entry point
mov edx,len ;message length
mov ecx,msg ;message to write
mov ebx,1 ;file descriptor (stdout)
mov eax,4 ;system call number (sys_write)
int 0x80 ;call kernel
mov eax,1 ;system call number (sys_exit)
int 0x80 ;call kernel
section .data
msg db 'Hello, world!', 0xa ;our dear string
len equ $ - msg ;length of our dear string
now i dont know what is happening in this line: msg db 'Hello, world!', 0xa
i know the meaning of msg db 'Hello, world!' but the problem rises when i see the comma and 0xa after that..
After some research i cam to know that the 0xa causes a line break but i just dont understand why is a comma used there?
Is it some sort of concatenation or something?
like the c(++) syntax: cout << "asdfsdf" << var;
or perhaps the Java syntax: System.out.println("Hello,"+var+"!"); or python syntax: print 'Yo '+var
please help...
That line is simply declaring a label named msg in the data segment. msg is pointing to a byte buffer initialized with the characters Hello, world!, immediately followed by a newline character (0x0A). The line after that is calculating the length of the string by taking the difference between the current address and the msg label. The len symbol will hold that length. The use of the comma is not an operator, it's simply just a separator between the values you are using to initialize the buffer.
Strings are treated specially in most (if not all) assembly languages to make it more convenient to write. That way you don't have to write out every individual character in that string.
The following declarations are equivalent:
str1 db 'abcde'
str2 db 0x61, 'bc', 'd', 101
; 'a' is 0x61 hex
; 'e' is 101 decimal
Just be warned that they usually don't automatically include a null terminator. This is why you would typically see a string declared like this:
message db 'Hello world', 0