I wanted to follow this guide : http://gcc.gnu.org/onlinedocs/libstdc++/manual/bk01pt12ch31s03.html
Here is some example code :
#include <numeric>
#include <vector>
#include <iostream>
#include <chrono>
using namespace std;
int main()
{
vector<int> in(1000);
vector<double> out(1000);
iota(in.begin(), in.end(), 1);
auto t = std::chrono::high_resolution_clock::now();
for(int i = 0; i < 100000; ++i)
accumulate(in.begin(), in.end(), 0);
auto t2 = std::chrono::high_resolution_clock::now();
cout << std::chrono::duration_cast<std::chrono::milliseconds>(t2 - t).count() << endl;
return 0;
}
I have the following results :
~:$ g++ test.cpp -std=c++11
~:$ ./a.out
900
~:$ g++ test.cpp -D_GLIBCXX_PARALLEL -std=c++11 -fopenmp -march=native
~:$ ./a.out
1026
When doing multiple runs, these two stays at about the same time. I have also tried with other algorithms, like sort, generate, find, transform... I have an i7, with hyperthreading enabled (4 logical cores). I run g++-4.8.1
Thanks
I think you need to try something a little more heavy. All your doing is adding int
s together. The overhead of creating the threads, etc. will be greater. Try replacing int
with std::string
and running the following code and compare the output:
int main()
{
vector<string> in(100000);
auto t = std::chrono::high_resolution_clock::now();
accumulate(in.begin(), in.end(), string(), [](string s1, string s2){ return s1 += s2 + "a" + "b";});
auto t2 = std::chrono::high_resolution_clock::now();
cout << std::chrono::duration_cast<std::chrono::milliseconds>(t2 - t).count() << endl;
}