How to erase letters at any position in a string in python?

Question

For example, my String = 'xx22xx_1x_xxxx-xxxx', x can be any letters. Now I want to delete the first two positions letters xx and seventh position 1, in order to get a NewString = '22xx_x_xxxx-xxxx'. Any function to erase letters at specific positions?

Answer 1

This will do it:

def erase(string, positions):
    return "".join([y for x,y in enumerate(string) if x not in positions])

demo:

>>> s='xx22xx_1x_xxxx-xxxx'
>>> erase(s, (0,1,7))
'22xx_x_xxxx-xxxx'
>>>