Here is a shortcut of my code:
//myClass.h
namespace toto
{
class myClass
{
friend void *myRoutine(void*);
private:
char* _name;
}
}
//myClass.cpp
using namespace toto;
void *myRoutine(void* arg)
{
myClass* foo = static_cast<myClass*>(arg);
if ( NULL != foo )
{
cout << foo->_name;
}
}
When compiling with GCC, I get an error "_name is private". I absolutly need that signature of function since it is used as a thread routine. And I'd like to avoid changing my attributes to public..
If somebody can help me, thanks !
Edit: In addition, myClass is defined in a namespace, and in the .cpp file I put a "using namespace ..." at the beginning.
Your friend declaration in myClass
, declares a toto::myRoutine
while your function definition defines a ::myRoutine
. Define myRoutine
in the same namespace as myClass
to fix your problem.