Ignoring zero by division instances in script

Question

Is there a way to ignore values in a list that create a division by zero in an iterative script instead of removing those problem values?

I'm thinking along the lines of if

if(x==0):
 break
elif(x!=0):
 continue

Where the values that aren't zero get to continue on through the script.

Answer 1

You can use list comprehension for a more efficient code,

from __future__ import division
num = [1,2,3,4,5,6,3,31,1,0,120,0,0]
divisor = 10
print [divisor/x for x in num if x != 0]

Output:

[10.0, 5.0, 3.3333333333333335, 2.5, 2.0, 1.6666666666666667, 3.3333333333333335, 0.3225806451612903, 10.0, 0.08333333333333333]