Assuming I have the following Clojure code:
(defn foo ^double []
(-
(* 123.31
(+ 4 5 6 (Math/sin 34.2))
123.31)
123))
Will gen-class produce byte code equivalent to compiling the following java code:
public static double foo(){
return (123.31 * (4 + 5 + 6 + Math.sin(34.2)) * 123.31) - 123;
}
Or in other words can I user Clojure as a very convenient DSL to produce efficient dynamic byte code?
Edit:
Ok, I did some test to illustrate my issue:
Here is java version:
public class FooTest {
public static double foo(double a, double b, double c){
return (a * (b + c + (b*c) + Math.sin(a)) * Math.log(b)) - b;
}
public static long benchmark(){
long start = System.currentTimeMillis();
for (double i = 0; i < 100000000.0; i++) { // 100 mln
double r = foo(i, i+1, i+2);
}
long end = System.currentTimeMillis();
return (end-start);
}
public static void main(String[] args) {
System.out.println("Time took: "+benchmark());
}
}
This produces the output: Time took: 39200
The clojure 'equivalent':
(defn foo ^double
(^double [a b c]
(-
(* a
(+ b c (* b c) (Math/sin a))
(Math/log b))
b)))
(time
(loop [i 0.0]
(when (< i 100000000)
(foo i (+ i 1) (+ i 2))
(recur (inc i)))))
That produces: "Elapsed time: 121242.902 msecs"
Which is 3 times slower.
Now my rephrased question is: How can I structure/hint clojure code so it avoids functions calls in code which is effectively primitive maths operations?
Edit2:
I have changed the test so it uses unchecked primitive maths operators:
(defn foo ^double
(^double [a b c]
(binding [*unchecked-math* true]
(-
(* a
(+ b c (* b c) (Math/sin a))
(Math/log b))
b))))
"Elapsed time: 64386.187 msecs" So it is almost 2 times better but still 1.6 times the java version.
Ok, I finally got identical performance of Clojure to java. Three things needed change:
The resulting code is:
(binding [*unchecked-math* true]
(defn foo ^double [^double a ^double b ^double c]
(-
(* a
(+ b c (* b c) (Math/sin a))
(Math/log b))
b)))
(binding [*unchecked-math* true]
(time
(loop [i (double 0.0)]
(when (< i 100000000)
(foo i (+ i 1) (+ i 2))
(recur (inc i))))))