I am scratching my head over this. For example I have:
Date
sometext
somtext
27-7-2013
What I want to do is I want to get the first date format string pattern after the Date keyword. Here is what I currently have:
(?i)(?<=date.*)\d+-\d+\d+
But unfortunately, I am getting nothing and if I just try to get all the string after the date keyword, e.g.
(?i)date.*
I am only getting the result as:
Date[CR]
I am using Expresso to test out my regular expressions. I am pretty new with using regex so I am not familiar with how to do things and stuff.
Please help! Thanks!
I would not use a lookbehind assertion in this case, also unlimited length lookbehinds are (I think) only supported by .net.
I would use a capturing group instead:
(?is)date.*?(\d{1,2}-\d{1,2}-\d{4})
You will find the date in the first capturing group.
See it here on Regexr
(?is) is enabling the case independent matching mode i and the single line mode s, that makes the . also match newline characters.
.*? is matching lazily any characters.
(\d{1,2}-\d{1,2}-\d{4}) matches one or two digits, a dash, one or two digits, a dash, then 4 digits.