Safe method to get computer IP on UNIX using Java

Question

I need to get computer IP from Ubuntu using Java. I tried with InetAddress.getLocalHost.getHostAddress().toString(); but it returns 127.0.0.1 . I was searching for solution and found out this code:

NetworkInterface ni = NetworkInterface.getByName("eth0");
    Enumeration<InetAddress> inetAddresses =  ni.getInetAddresses();


    while(inetAddresses.hasMoreElements()) {
        InetAddress ia = inetAddresses.nextElement();
        if(!ia.isLinkLocalAddress()) {
            System.out.println("IP: " + ia.getHostAddress());
        }
    }
}

This code worked for me but problem is when computer uses "eth1" interface or computer can use wireless adapter to connect to network (wlan0). On that situatuon program will fail. Can you guys advise me with safe method to get IP from UNIX systems ? Regards.

Answer 1

Although a computer can have multiple network interfaces and different IPs, some of the interfaces can also be loopback or not running. To be "safe" you might even have to check names of the interface to see if you use the IP address from desired one.

Following method will give you a list of ip addresses from non-loopback, up and running interfaces.

 public static List<InetAddress> getIPAddress() throws SocketException {

    List<InetAddress> ipAddresses = new ArrayList<InetAddress>();
    Enumeration e;
    e = NetworkInterface.getNetworkInterfaces();
    while (e.hasMoreElements()) {
        NetworkInterface ni = (NetworkInterface) e.nextElement();
        if (ni.isLoopback() || !ni.isUp()) continue;

        for (Enumeration e2 = ni.getInetAddresses(); e2.hasMoreElements(); ) {
            InetAddress ip = (InetAddress) e2.nextElement();
            ipAddresses.add(ip);
        }
    }
    return ipAddresses;
}