I'm using an existing bash script and want to send the output of 2 rsync commmands so that it is passed to a variable which will then be used later, See below,
rfiles=$(rsync -rvlpogt /svntags/tags/ /var/www/html/) && $(rsync -rvlpogt /svnbranch/branches/ /var/www/html/)
ecode=$?
newfil=$(echo $rfiles | grep -c "Number of files transferred: 0")
However, I only get the output of the 1st rsync sent to my mail. How do include the output of the 2nd rsync command as well along with the first?
Thank you.
The problem is with how your assignment is written. It's breaking up your line:
rfiles=$(rsync -rvlpogt /svntags/tags/ /var/www/html/) && $(rsync -rvlpogt /svnbranch/branches/ /var/www/html/)
into rfiles=$(rsync -rvlpogt /svntags/tags/ /var/www/html/) && $(rsync -rvlpogt /svnbranch/branches/ /var/www/html/)
Thus you get the output of just the first command in the variable. You'll need to change the command to
rfiles=$(rsync -rvlpogt /svntags/tags/ /var/www/html/ && rsync -rvlpogt /svnbranch/branches/ /var/www/html/)
To illustrate with another example:
samveen@precise:~$ a=$(echo 10) && $(echo 20)
-bash: 20: command not found
samveen@precise:~$ echo $a
10