Selenium: Not able to understand xPath

Question

I have some HTML like this:

<h4 class="box_header clearfix">
<span>
<a rel="dialog" href="http://www.google.com/?q=word">Search</a>
</span>
<small>
<span>
<a rel="dialog" href="http://www.google.com/?q=word">Search</a>
</span>
</h4>

I am trying to get the href here in Java using Selenium. I have tried the following:

selenium.getText("xpath=/descendant::h4[@class='box_header clearfix']/");
selenium.getAttribute("xpath=/descendant::h4[@class='box_header clearfix']/");

But none of these work. It keeps complaining that my xpath is invalid. Can someone tell me what mistake I am doing?

Answer 1

You should use getAttribute to get the href of the link. Your XPath needs a reference to the final node, plus the required attribute. The following should work:

selenium.getAttribute("xpath=/descendant::h4[@class='box_header clearfix']/a@href");

You could also modify your XPath so that it's a bit more flexible to change, or even use CSS to locate the element:

//modified xpath
selenium.getAttribute("//h4[contains(@class,'box_header')]/a@href");

//css locator
selenium.getAttribute("css=.box_header a@href");