Python - unpack struct into multiple tuples

Question

I'd like to know if there is a cleaner way to do the following in Python 2.7?

# Current working code!
(is_enabled,) = struct.unpack_from("<?", data)
cmd_speed = struct.unpack_from("<3h", data, 1)
tach_speed = struct.unpack_from("<3h", data, 1+2*3)

Specifically, I don't like manually keeping track of the offset into the next tuple. Ideally I'd like to be able to specify the data structure with a single format statement; Something like this:

# Hypothetical example, does not work! 
(is_enabled,), cmd_speed, tach_speed = struct.unpack("<(?),(3h),(3h)", data)

Answer 1

You could do it with one call to struct.unpack, but you'd still have to slice up the result yourself:

import struct
data = struct.pack('<?3h3h', True, 1,2,3,4,5,6)
result = struct.unpack('<?3h3h', data)
is_enabled = result[0]
cmd_speed = result[1:4]
tach_speed = result[4:7]

print(is_enabled, cmd_speed, tach_speed)

yields

(True, (1, 2, 3), (4, 5, 6))

---

Or, you could use this:

import struct
import itertools as IT

def unpack_formats(fmts, data):
    data = iter(data)
    return [struct.unpack(fmt, ''.join(IT.islice(data, struct.calcsize(fmt))))
            for fmt in fmts]

data = struct.pack('<?3h3h', True, 1,2,3,4,5,6)
fmts = ('<?', '<3h', '<3h')
(is_enabled,), cmd_speed, tach_speed = unpack_formats(fmts, data)
print(is_enabled, cmd_speed, tach_speed)

which yields

(True, (1, 2, 3), (4, 5, 6))

---

Although unpack_formats looks prettier, the following is actually faster (probably because there is no ''.join needed):

def unpack_formats2(fmts, data):
    result = []
    i = 0
    for fmt in fmts:
        size = struct.calcsize(fmt)
        j = i+size
        result.append(struct.unpack(fmt, data[i:j]))
        i = j
    return result

In [80]: %timeit unpack_formats(fmts, data)
100000 loops, best of 3: 3.51 us per loop

In [81]: %timeit unpack_formats2(fmts, data)
1000000 loops, best of 3: 1.61 us per loop