My question is more of a conceptual/learning one that applies in this specific instance. I'm doing an assignment, and I have a class called sensor, and a derived class called digitalSensor. One of the data members of sensor is "functioning". And, when I implement the print function for digitalSensor I need to print out a line based on whether the digital sensor is "functioning" or not.
essentially, I need to make an if statement in digitalSensor where it checks the value of "functioning". But Xcode tells me that "functioning is a private member of sensor". Since digitalSensor is derived from sensor, shouldn't it also have the "functioning" member variable? How do I check it in my creation of the digitalSensor print function?
Here is my sensor.h file:
#ifndef __Program_6__sensor__
#define __Program_6__sensor__
#include <iostream>
class sensor {
char* SensorName;
float energyDraw;
int functioning;
int onoff;
public:
sensor(char*n, float pc);
virtual void print();
void setOK(int K);
int getOK();
void setOnOff(int n);
int getOnOff();
};
//---------
class digitalSensor : public sensor {
int reading;
public:
digitalSensor(char*n, float pc);
virtual void print();
void setCurrentReading(int r);
int getCurrentReading();
};
class analogSensor : public sensor {
int Reading;
int minRead;
int maxRead;
public:
analogSensor(char *n, float pc, int mm, int mx);
virtual void print();
void setCurrentReading(int r);
int getCurrentReading();
};
#endif /* defined(__Program_6__sensor__) */
And here is my sensor.cpp file, my work on the print function is at the bottom:
#include "sensor.h"
#include "definitions.h"
using namespace std;
//--------SENSOR CLASS------------//
sensor::sensor(char *n, float pc) {
SensorName = (char*)malloc(strlen(n)+1);
energyDraw = pc;
functioning = WORKING;
onoff = OFF;
}
void sensor::print() {
cout << " Sensor: " << SensorName;
cout << " Power Consumption: " << energyDraw;
if (functioning == WORKING) {
cout << "\nSensor is functioning correctly\n";
if (onoff == ON) {
cout << "Sensor is On";
}
if (onoff == OFF) {
cout << "Sensor is Off";
}
}
if (functioning == NOTWORKING) {
cout << "Sensor is not functioning correctly";
}
}
void sensor::setOK(int k) {
functioning = k;
}
int sensor::getOK() {
return functioning;
}
void sensor::setOnOff(int n) {
onoff = n;
}
int sensor::getOnOff() {
return onoff;
}
//---------------------------------//
//*********DIGITAL SENSOR**********//
digitalSensor::digitalSensor(char *n, float pc) : sensor(n, pc){
reading = OFF;
}
void digitalSensor::print() {
sensor::print();
if (functioning == WORKING && onoff == ON) {
cout << "Current sensor reading is: " << reading;
}
if (digitalSensor.functioning == WORKING && digitalSensor.onoff == OFF) {
cout << "Current reading not available";
}
}
The error is two lines after "void digitalSensor::print()" there at the end.
thanks for any help you all can give! I'll make sure to reciprocate and answer newbie questions too someday once I learn this stuff!
In C++ the default visibility for class
members is private
, which means that fields and methods are not accessible from the outside, not even from subclasses. The solution is marking the concerned fields as protected
(same as private
, but accessible from subclass):
class sensor {
protected:
char* SensorName;
float energyDraw;
int functioning;
int onoff;
public:
sensor(char*n, float pc);
virtual void print();
void setOK(int K);
int getOK();
void setOnOff(int n);
int getOnOff();
};