This challenge gets to to some of the subtle aspects of the C language. My first stab at this follows.
int main(int argc, char *argv[]) {
int a,b,c,d,e,g,h,i;
int f[1];
double A,B,C,D,EFGHIJKLMNOPQRSTUVWXYZhijklmnopqrstuvwxyz_;
// Following line is a line using many ASCII characters. (Begins with a TAB)
{a =!~(0*b%c^d&e+f[g]|h-i)?A:B>C,D<EFGHIJKLMNOPQRSTUVWXYZhijklmnopqrstuvwxyz_/1.23456789;}
// Failed to use \ ` @ # $ " ' : and various control characters.
return (0);
}
How can I use \ backquote @ # $ " ' :
and maybe some more control characters?
Background: in creating code checkers and beautifiers, we run into various subtle C language issues. The above is a group self imposed exercise.
Note: ASCII is characters codes 0 - 127.
Note: Strings normally use pairs of quote marks and the line is limited to unique usages.
Perhaps you can put everything in a string, and go to the next line with a \
:
void main() {
int a,b,c,d,e,g,h,i,f[1];
double A,B,C,D,EFGHIJKLMNOPQRSTUVWXYZhijklmnopqrstuvwxyz_;
// Following line is a line using many ASCII characters. (Begins with a TAB)
{a =!~(0*b%c^d&e+f[g]|h-i)?A:B>C,D<EFGHIJKLMNOPQRSTUVWXYZhijklmnopqrstuvwxyz_/1.23456789;}"'`@#$\
";
}