I am currently using the following code. Which clone an element and changed an input in the clone to what I need it to be. There is a select in the clone as well that I need to change it's name to another val. How do I execute 2 children on the same clone command at the same time?
Code:
$(this).parent().parent()
.append($(this).parent()
.clone()
.children('input').attr('name', VAL)
.end()
);
I need something like this
$(this).parent().parent()
.append($(this).parent()
.clone()
.children('input').attr('name', VAL)
.children('select').attr('name', VAL2) // Where this does not target children of the input, but of the clone.
.end()
);
This answer is with some thanks to gdoron, but he refused to change his answer to the actual correct answer. If you need to edit multiple children in a clone or in any object simple use end and specify the next child.
$(this).parent().parent()
.append($(this).parent()
.clone()
.children('input').attr('name', VAL)
.end()
.children('select').attr('name', VAL2)
.end()
);