I have to execute a long process operation in a thread and continue by returning the result to a function. Here is my code :
Task<ProductEventArgs>.Factory.StartNew(() =>
{
try
{
// long operation which return new ProductEventArgs with a list of product
}
catch (Exception e)
{
return new ProductEventArgs() { E = e };
}
}).ContinueWith((x) => handleResult(x.Result), TaskScheduler.FromCurrentSynchronizationContext());
The problem is actually I don't have a timeout. I want to put a timer in order to return something like this :
new ProductEventArgs() { E = new Exception("timeout") };
if the timeout is reached. Can't use await/async. Thanks a lot !
This code does what you have expressed here:
var timeout = TimeSpan.FromSeconds(5);
var actualTask = new Task<ProductEventArgs>(() =>
{
var longRunningTask = new Task<ProductEventArgs>(() =>
{
try
{
Thread.Sleep(TimeSpan.FromSeconds(10)); // simulates the long running computation
return new ProductEventArgs();
}
catch (Exception e)
{
return new ProductEventArgs() { E = e };
}
}, TaskCreationOptions.LongRunning);
longRunningTask.Start();
if (longRunningTask.Wait(timeout)) return longRunningTask.Result;
return new ProductEventArgs() { E = new Exception("timed out") };
});
actualTask.Start();
actualTask.Wait();
Console.WriteLine("{0}", actualTask.Result.E); // handling E
As you see longRunningTask
is created with TaskCreationOptions.LongRunning
option. That way it will have a dedicated Thread
for it's execution and does not interfere with normal behavior of ThreadPool
by occupying a thread from there for too long - which will be needed for other thing like i.e. UI. That's important for long running tasks.
Note: You could then handle actualTask
with ContinueWith
but I wanted to express the essence here.