I am trying to remove just the last part of the url, Its a FTP URL.
Suppose, I have a URL like: > ftp://ftp.abc.com/public_html/somefolder/. After removing the last portion I should have it as: ftp://ftp.abc.com/public_html/.
I have tried using stringByDeletingLastPathComponenet
and URLByDeletingLastPathComponent
, but they dont remove the last portion correctly. They change the entire looks of the url.
for instance, after using the above said methods, here is the URL format i get ftp:/ftp.abc.com/public_html/. It removes one "/" in "ftp://", which is crashing my program.
How is it possible to removve just the last part without disturbing the rest of the URL ?
UPDATE:
NSURL * stringUrl = [NSURL URLWithString:string];
NSURL * urlByRemovingLastComponent = [stringUrl URLByDeletingLastPathComponent];
NSLog(@"%@", urlByRemovingLastComponent);
Using above code, I get the output as :- ftp:/ftp.abc.com/public_html/
Now try
NSString* filePath = @"ftp://ftp.abc.com/public_html/somefolder/.";
NSArray* pathComponents = [filePath pathComponents];
NSLog(@"\n\npath=%@",pathComponents);
if ([pathComponents count] > 2) {
NSArray* lastTwoArray = [pathComponents subarrayWithRange:NSMakeRange([pathComponents count]-2,2)];
NSString* lastTwoPath = [NSString pathWithComponents:lastTwoArray];
NSLog(@"\n\nlastTwoArray=%@",lastTwoPath);
NSArray *listItems = [filePath componentsSeparatedByString:lastTwoPath];
NSLog(@"\n\nlist item 0=%@",[listItems objectAtIndex:0]);
}
output
path=(
"ftp:",
"ftp.abc.com",
"public_html",
somefolder,
"."
)
lastTwoArray =somefolder/.
list item 0 =ftp://ftp.abc.com/public_html/