Little endian or Big endian

Question

#include <stdio.h>

union Endian
{
    int i;
    char c[sizeof(int)];
};

int main(int argc, char *argv[]) 
{
    union Endian e;
    e.i = 1;
    printf("%d \n",&e.i);
    printf("%d,%d,\n",e.c[0],&(e.c[0]));
    printf("%d,%d",e.c[sizeof(int)-1],&(e.c[sizeof(int)-1]));


}

OUTPUT:

1567599464 
1,1567599464,
0,1567599467

LSB is stored in the lower address and MSB is stored in the higher address. Isn't this supposed to be big endian? But my system config shows it as a little endian architecture.

Answer 1

You system is definitely little-endian. Had it been big-endian, the following code:

printf("%d,%d,\n",e.c[0],&(e.c[0]));

would print 0 for the first %d instead of 1. In little-endian 1 is stored as

00000001 00000000 00000000 00000000
^ LSB
^Lower Address

but in big-endian it is stored as

00000000 00000000 00000000 00000001
                           ^LSB
                           ^Higher Address  

And don't use the %d to print addresses of variables, use %p.