I have XSL:
<html xsl:version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns="http://www.w3.org/1999/xhtml">
<body>
<table>
<tr>
<td><b>Song</b></td>
<td><b>Track</b></td>
</tr>
<xsl:for-each select="results/result[Artist='Michael Jackson']">
<tr>
<td><xsl:value-of select="Song"/></td>
<td><xsl:value-of select="Track"/></td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
And source XML
<?xml version="1.0"?>
<results>
<result>
<Artist>
Michael Jackson
</Artist>
<Song>
Beat it
</Song>
<Track>
2
</Track>
</result>
</results>
The result yields no rows, where I expect to see a table with results, where Michael Jackson is the artist.
I have done some testing and I think the indent, or empty space in the source is getting in the way of the select.
When I use source...
<?xml version="1.0"?>
<results>
<result>
<Artist>Michael Jackson</Artist>
<Song>Beat it </Song>
<Track>2 </Track>
</result>
</results>
It works.
Unfortunately I have no control of the source format. I feel like there must be a simple answer as a lot of XML is indented this way.
Is there a trim function or wildcard I can use to make the [] select/filter work?
Many thanks
Use the normalize-space()
function:
<xsl:for-each select="results/result[normalize-space(Artist)='Michael Jackson']">