I have a problem in which I have a list of elements and I have to cycle through all instances of a particular /2 predicate to find which one has he highest number of matching elements in its list. In terms of implementation I can't seem to figure out how I should be updating the highest match so far and then stopping when there are no more.
findAnswer(MyList, HighMatchNum,_):-
answer(X,Y),
myIntersection(MyList, Y, NUM), //handles a single instance check and returns how many elements match.
NUM > HighMatchNum,
findAnswer(MyList, NUM, answer(X,Y)).
//Knowledge base
answer(sample1, [a,b,c,d]).
answer(sample2, [d,c,e]).
there is library(aggregate):
findAnswer(MyList, HighMatchNum, K) :-
aggregate_all(max(N, Key),
( answer(Key, List),
myIntersection(MyList, List, N)
),
max(HighMatchNum, K)).
myIntersection(MyList, List, N) :-
intersection(MyList, List, L),
length(L, N).
% Knowledge base
answer(sample1, [a,b,c,d]).
answer(sample2, [d,c,e]).
yields
?- findAnswer([a], C, K).
C = 1,
K = sample1.
?- findAnswer([d,e], C, K).
C = 2,
K = sample2.