BufferedImage Color Channel Mask

Question

I have found this code on JavaDoc, but I can't seem to understand it.

output.setRGB(x, y, (image.getRGB(x, y) & 0xff00ff00)
                    | ((image.getRGB(x, y) & 0xff0000) >> 16)
                    | ((image.getRGB(x, y) & 0xff) << 16));

All I know that this code turns blue color to red in a BufferedImage. but what if I want to replace blue with white or some other color and vice-versa?

I would appreciate any help.

Answer 1

When I work with color I use different idea:

    BufferedImage image = //create Buffered image
    int rgb = image.getRGB(x,y);   //get Rgb color value
    Color color = new Color(rgb);  // create color with this value
    Color resultColor = new Color(color.getRed(), color.getBlue(), color.getGreen()); //create new color change blue and green colors values
    image.setRGB(x,y,resultColor.getRGB());   //set color

I think this idea is easier to understand.

if you want to get white color use this :

    BufferedImage image = new BufferedImage();
    Color color = new Color(255,255,255);
    image.setRGB(x,y,color.getRGB());