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regexargumentstokenbraces

Regex match token with argument

A token can be like this {num} or {num:2} (2 being an arg)

I would like to achieve matching like this:

// no args
[0] = num

// args (anything after the colon and before the closing brace as one match is fine)
[0] = num
[1] = 2

I managed to match anything in the braces that was easy but my regex is too noob to get anything more complex than that! Thanks.

FYI I am using javascript and \{(.*?)\} matches all the contents within.

Solution

  • You could do something like this:

    \{(.*?)(?::(.*?))?\}

    And a test:

    > '{foo:bar}'.match(/\{(.*?)(?::(.*?))?\}/)
["{foo:bar}", "foo", "bar"]
> '{foo}'.match(/\{(.*?)(?::(.*?))?\}/)
["{foo}", "foo", undefined]
    • (.*?) non-greedily matches the first group.
    • (?:...) is a non-capturing group. It's just like a regular capturing group, but it doesn't get captured.
    • :(.*?) captures the stuff after the colon.
    • ? makes that last group (which contains the colon and the second capturing group) optional.