Part of my program is:
f = open('test.txt')
for line in f.readlines():
print 'test'
exit()
Why can't I exit the program immediately when first meet the exit? Instead, my program will exit while the loop has finished.
It happened in the interactive mode:
In [1]: f = open('test.txt', 'r')
In [2]: for line in f.readlines():
...: print 'test'
...: exit()
...:
test
test
test
test
test
test
exit
in IPython is not the same function as exit
in Python.
In IPython, exit
is an instance of IPython.core.autocall.ExitAutocall
:
In [6]: exit?
Type: ExitAutocall
String Form:<IPython.core.autocall.ExitAutocall object at 0x9f4c02c>
File: /data1/unutbu/.virtualenvs/arthur/local/lib/python2.7/site-packages/ipython-0.14.dev-py2.7.egg/IPython/core/autocall.py
Definition: exit(self)
Docstring:
An autocallable object which will be added to the user namespace so that
exit, exit(), quit or quit() are all valid ways to close the shell.
Call def: exit(self)
In [7]: type(exit)
Out[7]: IPython.core.autocall.ExitAutocall
It's definition looks like this:
class ExitAutocall(IPyAutocall):
"""An autocallable object which will be added to the user namespace so that
exit, exit(), quit or quit() are all valid ways to close the shell."""
rewrite = False
def __call__(self):
self._ip.ask_exit()
The self._ip.ask_exit()
call runs this method:
def ask_exit(self):
""" Ask the shell to exit. Can be overiden and used as a callback. """
self.exit_now = True
So it really does not exit IPython, it just sets a flag to exit when control returns to the IPython prompt.