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c#arraysloopscounter

Counting the number of times a value appears in an array


So what's a good, simple algorithm to create a loop in C# where every time a certain value appears in an array it adds 1 to a counter in another array?

For example I have this:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace ConsoleApplication22
{
    class Program
    {
        const int SIZE = 12;

        static void Main(string[] args)
        {
            int[] numbers = new int[SIZE] {5, 5, 5, 7, 7, 7, 9, 7, 9, 9, 9, 1};
           string[] letters = new string[SIZE] { "m", "m", "s", "m", "s", "s", "s", "m", "s", "s", "s", "s" };
            int[] values = new int[SIZE] {15, 22, 67, 45, 12, 21, 24, 51, 90, 60, 50, 44};
            string[] status = new string[SIZE] { "f", "m", "f", "a", "m", "f", "f", "f", "m", "f", "m", "f" };

            int[] Count = new int[4];
            int x = 0;
            int i = 0;

            for (i = 0; i < SIZE - 1; i++)
            {
                if (numbers[i] > 0 && numbers[i] < SIZE)
                {
                    x = Count[i];
                    Count[x]++;
                }
            }

            for (i = 0; i < 4; i++)
            {
                Console.WriteLine("{0}", Count[4]);
            }
        }
    }
}

I am only counting the number of times 4 numbers appear in the numbers array. Someone suggested I use the method in the first loop but it doesn't seem to be working and creates an error that the index is out of bounds in the array. I want to display the number of times each of those numbers(5, 7,9 and 1) appear in 4 rows.

EDIT: Without using LINQ or any other fancy thing like Dictionary or whatever.


Solution

  • You're getting an index out of bounds error because of this section:

    for (i = 0; i < SIZE - 1; i++)
    {
        if (numbers[i] > 0 && numbers[i] < SIZE)
        {
            x = Count[i];
    

    Notice that you're iterating through 0 to SIZE - 1 (11) when Count only has a size of 4.


    You can do this task pretty easily with LINQ though.

    int[] numbers = new int[SIZE] { 5, 5, 5, 7, 7, 7, 9, 7, 9, 9, 9, 1 };
    
    var count = numbers
        .GroupBy(e => e)
        .Where(e => e.Count() == 4)
        .Select(e => e.First());
    

    So it groups the numbers by their value, we then refine the list to only include groups of 4, then select the first of each to be left with a collection of ints.


    Here is a non-LINQ based solution using a Dictionary to store the count of numbers.

    int[] numbers = new int[SIZE] { 5, 5, 5, 7, 7, 7, 9, 7, 9, 9, 9, 1 };
    var dictionary = new Dictionary<int, int>();
    var numbersWithFour = new List<int>();
    
    foreach (var number in numbers)
    {
        if (dictionary.ContainsKey(number))
            dictionary[number]++;
        else
            dictionary.Add(number, 1);
    }
    
    foreach (var val in dictionary)
    {
        if (val.Value == 4)
        {
            numbersWithFour.Add(val.Key);
        }
    }
    

    With a little modification to your program you can get some results.

    int[] numbers = new int[SIZE] { 5, 5, 5, 7, 7, 7, 9, 7, 9, 9, 9, 1 };
    string[] letters = new string[SIZE] { "m", "m", "s", "m", "s", "s", "s", "m", "s", "s", "s", "s" };
    int[] values = new int[SIZE] { 15, 22, 67, 45, 12, 21, 24, 51, 90, 60, 50, 44 };
    string[] status = new string[SIZE] { "f", "m", "f", "a", "m", "f", "f", "f", "m", "f", "m", "f" };
    
    // Set the size of Count to maximum value in numbers + 1
    int[] Count = new int[9 + 1];
    int x = 0;
    int i = 0;
    
    for (i = 0; i < SIZE - 1; i++)
    {
        if (numbers[i] > 0 && numbers[i] < SIZE)
        {
            // Use value from numbers as the index for Count and increment the count
            Count[numbers[i]]++;
        }
    }
    
    for (i = 0; i < Count.Length; i++)
    {
        // Check all values in Count, printing the ones where the count is 4
        if (Count[i] == 4)
            Console.WriteLine("{0}", i);
    }
    

    Output:

    7
    9