How to check the status of call command in dos batch file

I have a batch file name xyz.bat with these content

 @echo off
 echo  1.Cleaning all four project.
 call apacheant\bin\ant -buildfile clean-all.xml

When the first call end it write on console build succeed or build failed.
How do i verify that this call failed or passed moreover on this condition basis i want to decide the next call execution.

echo  1.Building all four project.
call apacheant\bin\ant -buildfile build-all.xml
@echo on

Solution

echo  1.Building all four project.
call apacheant\bin\ant -buildfile build-all.xml >logfile.txt
findstr "succeed" logfile.txt >nul
if errorlevel 1 (echo Build failed) else (echo Build Succeeded)

Naturally, the echo ... could be replaced by 'set antstatus=SUCCEED` if required.

Don't try to use ERRORLEVEL to control the processing since MANY commands will change ERRORLEVEL to report their own status.

It may also be possible that ANT returns a status on termination. You could check with

echo %errorlevel%

after the ant step. If it returns an errorlevel, then you don't need to create and interpret the logfile.

The IF ERRORLEVEL syntax is

if errorlevel n Command_if_errorlevel_is_n_OR_GREATER_THAN_n