Makefile $(command) not working but `command` did

Question

The thing is when I was writing a Makefile for my project, when I needed to detect the current branch name, in a make rule I did this :

check_branch:
    if [ "$(git rev-parse --abbrev-ref HEAD)" == "master" ]; then \
    echo "In master"
    else \
    echo "Not in master"; \
    fi

When I called make check_branch, the "$(git rev-parse --abbrev-ref HEAD)" didn't work, it returned "" empty string. But instead when I changed $() to ` `, it worked perfectly.

check_branch:
    if [ "`git rev-parse --abbrev-ref HEAD`" == "master" ]; then \
    echo "In master"
    else \
    echo "Not in master"; \
    fi

Why is $() not working but `` did? Only for the "git" command.

Note that in my Makefile, I used $() normally in many rules.

Thanks :)

Answer 1

Inside recipes you have to escape dollar signs in order to get them interpreted by the shell. Otherwise, Make treats $(git ...) as a built-in command or a variable and tries to evaluate it (of course, unsuccessfully).

check_branch:
    if [ "$$(git rev-parse --abbrev-ref HEAD)" == "master" ]; then \
    ...