I have a directory with a lot of subdirectories, and I want to list all its files with a certain extension on each line, including the (sub)directory they're in. I'm now using:
ls /home/directory -R | grep ".ext" > files.txt
That does not give me the output I'm looking for... Ideally I would like an output that looks something like this:
/home/directory/subdirectory1/file1.ext 4.3Mb
/home/directory/subdirectory1/subsubdir1/file2.ext 3.3Mb
/home/directory/subdirectory2/file3.ext 4.6Mb
/home/directory/subdirectory3/file4.ext 5.2Mb
... etc
Or even better, with the directories and the filenames in separate columns:
/home/directory/subdirectory1/ file1.ext 4.3Mb
/home/directory/subdirectory1/subsubdir1/ file2.ext 3.3Mb
/home/directory/subdirectory2/ file3.ext 4.6Mb
/home/directory/subdirectory3/ file4.ext 5.2Mb
... etc
Any ideas on how to do this? Many thanks!
find putty -type f -name '*.c' -printf "%h\t%f\t%s\n" | column -t
Will produce something like this
putty sshzlib.c 38615
putty notiming.c 584
putty/charset macenc.c 7129
putty/charset sbcs.c 1190
If you want the entire path, present your directory argument to find as an absolute directory path from root.