I am a novice at using exception handling. I am using the mechanize module to scrape several websites. My program fails frequently because the connection is slow and because the requests timeout. I would like to be able to retry the website (on a timeout, for instance) up to 5 times after 30 second delays between each try.
I looked at this stackoverflow answer and can see how I can handle various exceptions. I also see (although it looks very clumsy) how I can put the try/exception inside a while loop to control the 5 attempts ... but I do not understand how to break out of the loop, or "continue" when the connection is successful and no exception has been thrown.
from mechanize import Browser
import time
b = Browser()
tried=0
while tried < 5:
try:
r=b.open('http://www.google.com/foobar')
except (mechanize.HTTPError,mechanize.URLError) as e:
if isinstance(e,mechanize.HTTPError):
print e.code
tried += 1
sleep(30)
if tried > 4:
exit()
else:
print e.reason.args
tried += 1
sleep(30)
if tried > 4:
exit()
print "How can I get to here after the first successful b.open() attempt????"
I would appreciate advice about (1) how to break out of the loop on a successful open, and (2) how to make the whole block less clumsy/more elegant.
You don't have to repeat things in the except block that you do in either case.
from mechanize import Browser
import time
b = Browser()
tried=0
while True:
try:
r=b.open('http://www.google.com/foobar')
except (mechanize.HTTPError,mechanize.URLError) as e:
tried += 1
if isinstance(e,mechanize.HTTPError):
print e.code
else:
print e.reason.args
if tried > 4:
exit()
sleep(30)
continue
break
Also, you may be able to use while not r:
depending on what Browser.open
returns.
Edit: roadierich showed a more elegant way with
try:
doSomething()
break
except:
...
Because an error skips to the except block.